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integration_by_parts [2023/06/08 08:20] spencerintegration_by_parts [2023/06/08 08:21] (current) – [Integration by Parts II (the formal adjoint of the exterior derivative)] spencer
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 $$(d\alpha, \beta) = (\alpha, \delta \beta) + \int_{\partial M} \langle \alpha, \iota_{\nu} \beta\rangle \mathrm{vol}_{\partial M}.$$ $$(d\alpha, \beta) = (\alpha, \delta \beta) + \int_{\partial M} \langle \alpha, \iota_{\nu} \beta\rangle \mathrm{vol}_{\partial M}.$$
 Probably. Would have to check whether boundary terms arise in the first step where we move $e(\omega^i)$ to the other side too. Probably. Would have to check whether boundary terms arise in the first step where we move $e(\omega^i)$ to the other side too.
 +Certainly in the compactly supported case $(d\alpha,\beta) = (\alpha, \delta \beta)$ holds just fine.
 +Of course, we also have $\delta = d^* = (-1)^{|\alpha| + 1} \star^{-1} d \star$ for $\star$ the Hodge star operator.
integration_by_parts.1686226840.txt.gz · Last modified: by spencer